@author jackzhenguo @desc @date 2019/4/6
def top1(lst): return max(lst, default='列表为空', key=lambda v: lst.count(v))
测试举例：
lst = [1, 3, 3, 2, 1, 1, 2] r = top1(lst) print(f'{lst}中出现次数最多的元素为:{r}') # [1, 3, 3, 2, 1, 1, 2]中出现次数最多的元素为:1